**Problem:** Given: - L1 = 200mH
- L2 = 800 mH
- L3 = 1.2H
| Find: L_{T} | | |

**Procedure:** | |

1. Set up the appropriate equation L_{T} = L_{1} + L_{2} + L_{3} | |

2. Substitute the known values LT = 200mH + 800mH + 1000mH | All terms must be expressed in the same units. | |

3. Do the math 200mH + 800mH + 1000mH = 2000mH | |

4. Normalize the result for engineering notation 2000mH = 2H | |

**Solution** L_{T} = 2H | |