Problem 1

Remove the parentheses:

(2y + 4)(3y + 2)

Procedure
Multiply first terms (2y + 4)(3y + 2)

6y2

Multiply first and second (2y + 4)(3y + 2)

4y

Multiply second and first (2y + 4)(3y + 2)

12y

Multiply second and second (2y + 4)(3y + 2)

8

Sum the results and combine like terms 6y2 + 4y + 12y + 8 = 6y2 + 16y + 8
Solution

(2y + 4)(3y + 2) = 6y2 + 16y + 8

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