Calculate the inductive reactance of a 500mH inductor that is operating at 250kHz

1. Set up the appropriate equation X_{L} = 2pfL

X_{L} = 2pfL

2. Substitute the known values X_{L} = 6.28(250 x 10^{3})(500 x 10^{-3})

X_{L} = 6.28(250 x 10^{3})(500 x 10^{-3})

3. Complete the math

X_{L} = 785 x 10^{3}

X_{L} = 785kW

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