Given:
V_{t} = 1.3 V f = 3.6 MHz C_{1} = 3.6 nF C_{2} = 884.1 pF C_{3} = 961.0 pF

Find:
C_{T}, X_{T}, I_{t}, q_{t} X_{C1}, V_{C1}, I_{C1} X_{C2}, V_{C2}, I_{C2} X_{C2}, V_{C3}, I_{C3} 
Solution:
C_{T} = 1.2 nF X_{T} = 35.9 W I_{t} = 36.1 mA q_{t} = 90° X_{C1} = 12 W V_{C1} = 433.8 mV I_{C1} = 36.1 mA X_{C2} = 50 W V_{C2} = 866.1 mV I_{C2} = 17.3 mA X_{C3} = 46 W V_{C3} = 866.1 mV I_{C3} = 18.8 mA
